Part 28 of 30 · QuadraticsSee the whole course

Factored form of a quadratic: reading the roots

Short answer

In factored form, y = a(x − p)(x − q), the roots are x = p and x = q. They are where the parabola lands on the x-axis. A product is zero only when one of its brackets is zero, and that is why the roots can be read straight off.

What a root is

A root of a quadratic, also called a zero or an x-intercept, is an x that makes y equal to 0. On the graph, it is a spot where the parabola crosses the x-axis. A quadratic can have two roots, one, or none.

The zero product property

If two numbers multiply to give 0, at least one of them must be 0. So in (x − 1)(x − 5) = 0, either x − 1 = 0 or x − 5 = 0. That gives x = 1 or x = 5. This works only when the other side is exactly 0.

Example 1: y = (x − 1)(x − 5)

Roots: x − 1 = 0 gives x = 1, and x − 5 = 0 gives x = 5.
The vertex is halfway between the roots, at x = (1 + 5) ÷ 2 = 3. The height there is (3 − 1)(3 − 5) = 2 × (−2) = −4, so the vertex is (3, −4).
Expanded, it is x² − 6x + 5.

The figure below starts with this one. Move the roots and watch the vertex stay in the middle.

y = (x − 1)(x − 5)
  1. (x − 1) = 0 at x = 1, and (x − 5) = 0 at x = 5
  2. vertex halfway between the roots: x = (1 + 5) ÷ 2 = 3
  3. vertex height: −4, so the vertex is (3, −4)
A product is zero only when one bracket is zero, so it crosses the x-axis at x = 1 and x = 5. It is a bowl.

Example 2: mind the plus sign

y = (x + 2)(x − 4). The bracket (x + 2) is zero when x = −2, not 2.
The roots are −2 and 4. The vertex is at x = (−2 + 4) ÷ 2 = 1, with height (3)(−3) = −9, so (1, −9).

Example 3: a missing bracket and a double root

y = x(x − 6): x is zero at x = 0, and x − 6 is zero at x = 6. The roots are 0 and 6, and the vertex is (3, −9).
y = (x − 3)²: both brackets are the same, so there is one root, x = 3. The parabola just touches the x-axis there.

What a number in front does

With y = −(x − 1)(x − 5) the roots are still 1 and 5, but the minus flips the parabola into an arch with the vertex at (3, 4). A number in front never changes the roots, only the height and direction. You can try it with the button in the figure.

Watch it explained in under a minute

The same idea, narrated step by step. Square version for sharing: download the 1:1 video.

The four mistakes to avoid

Try it yourself

Tap a question to see the answer.

1. y = (x − 2)(x − 7): find the roots and the x of the vertex.

Roots 2 and 7. The vertex is halfway: x = (2 + 7) ÷ 2 = 4.5.

2. y = (x + 3)(x + 1): find the roots and the vertex.

Roots −3 and −1. The vertex is at x = −2, with height (1)(−1) = −1, so (−2, −1).

3. y = −2(x − 4)(x + 4): find the roots and the vertex.

Roots 4 and −4. The vertex is at x = 0, with height −2(−4)(4) = 32, so (0, 32), the top of an arch.

Where this fits in

Reading roots from factors is easy. The real work is getting the factors in the first place. That is next: solve a quadratic by factoring.

Quick answers

Questions about this topic

What are the roots of a quadratic?

The values of x that make y equal to 0. They are also called zeros or x-intercepts, and on the graph they are where the parabola crosses the x-axis.

How do you find the roots from factored form?

Set each bracket equal to 0 and solve. For y = (x − 1)(x − 5), x − 1 = 0 gives x = 1 and x − 5 = 0 gives x = 5.

Where is the vertex compared with the roots?

Exactly halfway between them. The x-coordinate of the vertex is the average of the two roots.

What if both brackets are the same?

Then there is one root, called a double root, and the parabola just touches the x-axis there. For example (x − 3)² has the root 3.

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